Chapter 20 - Electric Potential and Electric Potential Energy - Problems and Conceptual Exercises - Page 720: 61

(a) $4.0\ nF$ (b) $6.6\ C$

(a) We know that $C=\frac{K\epsilon_{\circ}A}{d}$ We plug in the known values to obtain: $C=\frac{(1.00059)(8.85\times 10^{-12})(0.50\times 10^3)}{550}$ $C=4.0nF$ (b) As $Q_{max}=CV_{max}$ $Q_{max}=CE_{max}d$ We plug in the known values to obtain: $Q_{max}=(4.0\times 10^{-9})(3.0\times 10^6)(550)$ $Q_{max}=6.6C$