Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 20 - Electric Potential and Electric Potential Energy - Problems and Conceptual Exercises - Page 720: 51

Answer

$1.8V$

Work Step by Step

We can determine the required potential difference as follows: $V=\frac{Q}{C}$ We plug in the known values to obtain: $V=\frac{5.8\mu C}{3.2\mu F}$ $V=1.8V$
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