Answer
$Q=3.6 \mu C$
Work Step by Step
The charge on a capacitor is equal to $$Q=CV$$ Substituting known values of $C=0.40 \mu F$ and $V=9.0V$ yields a charge of $$Q=(0.40\mu F)(9.0V)=3.6 \mu C$$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 20 - Electric Potential and Electric Potential Energy - Problems and Conceptual Exercises - Page 720: 50
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