Chapter 20 - Electric Potential and Electric Potential Energy - Problems and Conceptual Exercises - Page 720: 69

(a) $Q=0.29C$ (b) $U=48J$

(a) We know that $Q=CV$ We plug in the known values to obtain: $Q=(890\times 10^{-6})(330)$ $Q=0.29C$ (b) As $U=\frac{1}{2}CV^2$ We plug in the known values to obtain: $U=\frac{1}{2}(890\times 10^{-6})(330)^2$ $U=48J$