Answer
$15KV$
Work Step by Step
We can find the required voltage as
$\Delta V=E\Delta S$
We plug in the known values to obtain:
$\Delta V=(3.0\times 10^6)(0.0050)$
$\Delta V=15KV$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 20 - Electric Potential and Electric Potential Energy - Problems and Conceptual Exercises - Page 720: 59
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