Answer
(a) $1.87\mu m$
(b) $6.9\mu m$
Work Step by Step
(a) For air, the separation is given as
$d=\frac{k\epsilon_{\circ}A}{C}$
We plug in the known values to obtain:
$d=\frac{(3.7)(8.85\times 10^{-12})(3.45\times 10^{-4})}{1630\times 10^{-12}}$
$d=1.87\times 10^{-6}=1.87\mu m$
(a) For paper, the separation is given as
$d=\frac{k\epsilon_{\circ}A}{C}$
We plug in the known values to obtain:
$d=\frac{(3.7)(8.85\times 10^{-12})(3.45\times 10^{-4})}{1330\times 10^{-12}}$
$d=6.9\times 10^{-6}=6.9\mu m$
