Answer
(a) $19KV$
(b) decrease
(c) $9.7KV$
Work Step by Step
(a) We know that
$V=\frac{Qd}{k\epsilon_{\circ}A}$
We plug in the known values to obtain:
$V=\frac{4.7\times 10^{-6}(0.88\times 10^{-3})}{(2.0)(8.85\times 10^{-12})(0.012)}$
$V=19KV$
(b) As V is inversely proportional to dielectric constant k, hence the answer to part(a) will decrease if k is increased.
(c) We know that
$V=\frac{Qd}{k\epsilon_{\circ}A}$
We plug in the known values to obtain:
$V=\frac{4.7\times 10^{-6}(0.88\times 10^{-3})}{(4.0)(8.85\times 10^{-12})(0.012)}$
$V=9.7KV$
