Answer
(a) $0.78cm/s$
(b) $0.13cm/s$
Work Step by Step
(a) We can find the required speed as follows:
$v=\frac{\frac{\Delta V}{\Delta t}}{A}$
We plug in the known values to obtain:
$v=\frac{5.5\times 10^{-6}cm^3/s}{\pi(\frac{1}{2}(0.0030cm))^2}=0.78cm/s$
(b) We can find the required speed as follows:
$v=\frac{\frac{\Delta V}{\Delta t}}{A}$
We plug in the known values to obtain:
$v=\frac{\frac{5.5\times 10^{-6}cm^3/s}{340}}{\pi(\frac{1}{2}(0.0030cm))^2}=0.13cm/s$
