Answer
a) $v=3.82m/s$
b) $v=73.9m/s$
c) equal
Work Step by Step
(a) We can find the required speed as follows:
$v=\frac{\Delta m}{\Delta t}(\frac{4}{\rho \pi d^2})$
We plug in the known values to obtain:
$v=(3.11)(\frac{4}{(1000)\pi(0.0322)^2})$
$v=3.82m/s$
(b) We can find the required speed as follows:
$v=\frac{\Delta m}{\Delta t}(\frac{4}{\rho \pi d^2})$
We plug in the known values to obtain:
$v=(3.11)(\frac{4}{(1000)\pi(0.00732)^2})$
$v=73.9m/s$
(c) We know that for an incompressible fluid, the conservation of mass implies that what goes in equals what comes out. Thus, the mass of flow rates in the nozzle and hose are equal.
