Answer
a) $V=3.68\times 10^{-4}m^3$
b) $7.93\times 10^3Kg/m^3$
Work Step by Step
(a) The block can be determined as
$V=\frac{T_w-T_A}{(\rho_A-\rho_W)g}$
We plug in the known values to obtain:
$V=\frac{25-25.7}{(806-1000)(9.81)}$
$V=3.68\times 10^{-4}m^3$
(b) We can find the density of the block as
$\rho_{block}=\frac{T_w}{gV}+\rho_w$
We plug in the known values to obtain:
$\rho_{block}=\frac{25.0}{(9.81)(3.68\times 10^{-4})}+1000=7.93\times 10^3Kg/m^3$
