Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 15 - Fluids - Problems and Conceptual Exercises - Page 533: 51

Answer

$39\frac{m}{s}$

Work Step by Step

We know that $A_1v_1=A_2v_2$ $(\frac{\pi d_1^{2}}{4})v_1=(\frac{\pi d_2^{2}}{4})v_2$ This can be rearranged as: $v_2=(\frac{d_1}{d_2})^2v_1$ We plug in the known values to obtain: $v_2=(\frac{3.4cm}{0.57})^2=39\frac{m}{s}$
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