Answer
$210Kg$
Work Step by Step
We can find the maximum mass as
$W_{max}=F_B-W{am}$
$\implies m_{max}g=\rho_{H_2O}V_{am}g-m_{am}g$
This simplifies to:
$m_{max}=\rho_{H_2O}V_{am}-m_{am}$
We plug in the known values to obtain:
$m_{max}=(1000)(2.3)(0.66)(0.14)-0.22=210Kg$
