Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 15 - Fluids - Problems and Conceptual Exercises - Page 533: 46

Answer

(a) $750\frac{Kg}{m^3}$ (b) increases

Work Step by Step

(a) We know that $\rho_{log}=\rho_w{\frac{V_{submerged}}{V}}$ We plug in the known values to obtain: $\rho=(1000)(\frac{3}{4})=750\frac{Kg}{m^3}$ (b) The portion of the log carried increases because the density of the displaced fluid is directly proportional to the bouyant force.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.