Answer
$16min$
Work Step by Step
We know that
$v_{pool}=\frac{\frac{1}{4}\pi d_{hose}^2}{\frac{1}{4}\pi d_{pool}^2}v_{hose}=(\frac{d_{hose}}{d_{pool}})^2v_{hose}$
We plug in the known values to obtain:
$v_{pool}=(\frac{0.029}{2.0})^2(1.3)=2.7\times 10^{-4}\frac{m}{s}$
Now we can find the required time as
$t=\frac{h}{v_{pool}}$
We plug in the known values to obtain:
$t=\frac{0.26}{2.7\times 10^{-4}}=960\times (\frac{1min}{60s})=16min$
