Answer
$\sqrt{(1.00\times 10^7m)h}$
Work Step by Step
We can find the radius of the largest spherical asteroid as follows:
$R_A=\sqrt{\frac{3gh}{4\pi G\rho}}$
We plug in the known values to obtain:
$R_A=\sqrt{\frac{3(9.81m/s^2)}{4\pi(6.67\times 10^{-11}N.m^2/kg^2)(3500Kg/m^3)}}$
$R_A=\sqrt{(1.00\times 10^7m)h}$
