Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 12 - Gravity - Problems and Conceptual Exercises - Page 412: 72

Answer

$M=1.85\times 10^{24}Kg$

Work Step by Step

We know that $M=\frac{R^2v_i^2}{2Gh}$ We plug in the known values to obtain: $M=\frac{(3860\times 10^3)^2(3.0)^2}{2(6.67\times 10^{-11})(0.58)}$ $M=1.85\times 10^{24}Kg$
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