Answer
$M=1.85\times 10^{24}Kg$
Work Step by Step
We know that
$M=\frac{R^2v_i^2}{2Gh}$
We plug in the known values to obtain:
$M=\frac{(3860\times 10^3)^2(3.0)^2}{2(6.67\times 10^{-11})(0.58)}$
$M=1.85\times 10^{24}Kg$
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