Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 12 - Gravity - Problems and Conceptual Exercises - Page 412: 66

Answer

$A \lt B \lt C$

Work Step by Step

The gravitational force on object A is given as $F_A=\frac{GM(2M)}{L^2}+\frac{GM(3M)}{(2L)^2}=\frac{11}{4}\frac{GM^2}{L^2}$ For object B $F_B=\frac{GM(2M)(3M)}{L^2}+\frac{GM(2M)}{(L)^2}=4\frac{GM^2}{L^2}=\frac{16}{4}\frac{GM^2}{L^2}$ For object C $F_C=\frac{G(3M)(2M)}{L^2}+\frac{GM(3M)}{(2L)^2}=4\frac{GM^2}{L^2}=\frac{27}{4}\frac{GM^2}{L^2}$ Now, we can rank A, B and C in order of increasing gravitational force as $A \lt B \lt C$
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