Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 12 - Gravity - Problems and Conceptual Exercises - Page 412: 57

Answer

It is 10 times that of the Earth.

Work Step by Step

We can compare the escape speed of the planet with that of the Earth as follows: $\frac{v_{esc,planet}}{v_{ecs, Earth}}=\frac{\sqrt{2GM_p/R_p}}{\sqrt{2GM_E/R_E}}$ $\frac{v_{esc,planet}}{v_{ecs, Earth}}=\sqrt{\frac{M_p R_E}{M_E R_p}}=\sqrt{\frac{(10M_E)R_E}{M_E(\frac{1}{4}R_E)}}=\sqrt{100}=10$ $v_{esc,p}=10v_{esc, Earth}$
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