Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 12 - Gravity - Problems and Conceptual Exercises - Page 412: 67

Answer

$B\lt C\lt A$

Work Step by Step

Initial acceleration for object A is given as $a_A=\frac{F_A}{m_A}=\frac{11}{4}\frac{GM}{L^2}$ For object B $a_B=\frac{F_B}{m_B}$ $a_B=\frac{\frac{4GM^2}{L^2}}{2M}$ $a_B=2\frac{GM}{L^2}$ For object C $a_C=\frac{F_C}{m_C}$ $\implies a_C=\frac{27}{4}\frac{GM^2/L^2}{3M}$ $a_c=\frac{9}{4}\frac{GM}{L^2}$ Now we can rank the objects A, B and C in order of their increasing initial acceleration as follows: $B\lt C\lt A$
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