Answer
$1.73Km/s$
Work Step by Step
We can find the required speed as follows:
$v_f=\sqrt{v_i^2+\frac{2GM_Mh}{R_M(R_M+h)}}$
We plug in the known values to obtain:
$v_f=\sqrt{(1630)^2+\frac{2(6.67\times 10^{-11})(7.35\times 10^{22})(110\times 10^3)}{(1.74\times 10^6)(1.85\times 10^6)}}$
$v_f=1730m/s=1.73Km/s$
