Answer
(a) $219Kg.\frac{m}{s}$
(b) $1.09\times 10^3Kg.\frac{m^2}{s}$
Work Step by Step
(a) We can find the linear momentum as
$p=mv$
We plug in the known values to obtain:
$p=(65.3)(3.35)$
$p=219Kg.\frac{m}{s}$
(b) The angular momentum can be determined as
$L=rmv$
We plug in the known values to obtain:
$L=(5.00)(63.5)(3.35)$
$L=1.09\times 10^3Kg.\frac{m^2}{s}$
