Answer
$228Kg$
Work Step by Step
We can find the mass as
$M=\frac{2F}{\alpha R}$
$M=\frac{2F\Delta t}{\Delta \omega R}$
We plug in the known values to obtain:
$M=\frac{2(42.2)(3.50)}{(0.0860rev/s\times 2\pi rad/rev)(2.40)}$
$M=228Kg$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 11 - Rotational Dynamics and Static Equilibrium - Problems and Conceptual Exercises - Page 369: 48
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