Answer
$14\frac{m}{s^2}$
Work Step by Step
As we know that
$\Sigma F_y=T_2-Mg=Ma$
This can be rearranged as:
$a=\frac{T_2}{M}-g$
We plug in the known values to obtain:
$a=\frac{16}{0.67}-9.81=14\frac{m}{s^2}$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 11 - Rotational Dynamics and Static Equilibrium - Problems and Conceptual Exercises - Page 369: 50
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