Answer
$7.05\times 10^{33}Kg.\frac{m^2}{s}$
Work Step by Step
The angular momentum can be determined as
$L=I\omega$
$\implies L=(\frac{2}{3}MR^2)(\frac{2\pi}{T})$
We plug in the known values to obtain:
$L=\frac{4\pi(5.97\times 10^{24})(6.37\times 10^6)^2}{5(86400)}$
$L=7.05\times 10^{33}Kg.\frac{m^2}{s}$
