Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 11 - Rotational Dynamics and Static Equilibrium - Problems and Conceptual Exercises - Page 369: 47

Answer

(a) less than (b) $3.22N$

Work Step by Step

(a) We know that the tension in the rope should be less than the weight of the bucket. If these two forces were equal then they would balance each other and as a result there would be no acceleration. (b) We can calculate the tension in the string as follows: $a=(\frac{M}{M-\frac{1}{2}m})g$ We plug in the known values to obtain: $a=(\frac{2.85}{2.85+\frac{1}{2}(0.742)})(9.81)$ $a=8.68m/s^2$ Now $T=\frac{1}{2}ma$ $\implies T=\frac{1}{2}(0.742)(8.68)$ $T=3.22N$
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