Answer
$8.6\times 10^{-5}Kg\frac{m^2}{s}$
Work Step by Step
The angular momentum can be determined as
$L=I\omega$
$L=(mr^2)\omega $
We plug in the known values to obtain:
$L=(0.0011)(0.15)^2(33\frac{1}{3}\frac{rev}{min})(2\pi\frac{rad}{rev})(\frac{1min}{60s})$
$L=8.6\times 10^{-5}Kg\frac{m^2}{s}$
