Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 11 - Rotational Dynamics and Static Equilibrium - Problems and Conceptual Exercises - Page 370: 57

Answer

(a) $156Kg.\frac{m}{s}$ (b) $936Kg.\frac{m^2}{s}$

Work Step by Step

We know that $p=mv$ We plug in the known values to obtain: $p=(58.2)(2.68)$ $p=156Kg.\frac{m}{s}$ Now the angular momentum can be calculated as $L=rmv$ We plug in the known values to obtain: $L=(6.00)(58.2)(2.68)$ $L=936Kg.\frac{m^2}{s}$
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