Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 22 - Wave Optics - Exercises and Problems - Page 649: 6

Answer

$0.221\;\rm mm$

Work Step by Step

We know, in a double-slit experiment, that $$\Delta y=\dfrac{\lambda L}{d}$$ where $\Delta y$ is the distance between two bright fringes, $L$ is the separation distance between the slit and the screen, and $d$ is the distance between the two slits. Thus, $$d =\dfrac{\lambda L}{ \Delta y}$$ Plugging the known; $$d =\dfrac{(589\times 10^{-9}) (1.50)}{(4\times 10^{-3})}=\bf 0.000221\;\rm m$$ $$d =\color{red}{\bf 0.221}\;\rm mm$$
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