Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 22 - Wave Optics - Exercises and Problems - Page 649: 2

Answer

The unknown wavelength is $~~465~nm$

Work Step by Step

We can write an expression when there is double slit interference: $d~sin~\theta_m = m~\lambda$ Let $\lambda_1 = 620~nm$ We can find $\lambda_2$: $4~\lambda_2 = 3~\lambda_1$ $\lambda_2 = 0.75~\lambda_1$ $\lambda_2 = (0.75)(620~nm)$ $\lambda_2 = 465~nm$ The unknown wavelength is $~~465~nm$
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