Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 22 - Wave Optics - Exercises and Problems - Page 649: 5

Answer

$0.36\;\rm mm$

Work Step by Step

We know, in a double-slit experiment, that $$\Delta y=\dfrac{\lambda L}{d}$$ where $\Delta y$ is the distance between two bright fringes, $L$ is the separation distance between the slit and the screen, and $d$ is the distance between the two slits. Thus, $$d=\dfrac{\lambda L}{\Delta y}$$ Plugging the known; $$d=\dfrac{(600\times 10^{-9})(2)}{\frac{1}{3}\times 10^{-2}}=0.00036\;\rm m$$ $$d=\color{red}{\bf0.36}\;\rm mm$$
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