Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 22 - Wave Optics - Exercises and Problems - Page 649: 14

Answer

The unknown wavelength is $~~396~nm$

Work Step by Step

We can write an expression for the angles of the diffraction orders: $sin~\theta_m = \frac{m~\lambda}{d}$ Let $\lambda_2$ be the unknown wavelength. We can find the value of $\lambda_2$: $\frac{(5)~\lambda_2}{d} = \frac{(3)~\lambda_1}{d}$ $\lambda_2 = \frac{(3)~\lambda_1}{5}$ $\lambda_2 = \frac{(3)~(660~nm)}{5}$ $\lambda_2 = 396~nm$ The unknown wavelength is $~~396~nm$
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