Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 22 - Wave Optics - Exercises and Problems - Page 649: 1

Answer

$\theta_3 = 0.02325~rad$ $\theta_3 = 1.33^{\circ}$

Work Step by Step

We can write an expression when there is double slit interference: $d~sin~\theta_m = m~\lambda$ We can find the angle in radians when $m = 3$: $d~sin~\theta_m = m~\lambda$ $sin~\theta_m = \frac{m~\lambda}{d}$ $sin~\theta_3 = \frac{(3)~(0.620~\mu m)}{80~\mu m}$ $sin~\theta_3 = 0.02325$ $\theta_3 = sin^{-1}~(0.02325)$ $\theta_3 = 0.02325~rad$ We can convert this angle to degrees: $\theta_3 = (0.02325~rad)(\frac{180^{\circ}}{\pi~rad})$ $\theta_3 = 1.33^{\circ}$
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