Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 22 - Wave Optics - Exercises and Problems - Page 649: 11

Answer

The grating has $~~513~~$ lines per millimeter.

Work Step by Step

We can write an expression for the angles of the diffraction orders: $sin~\theta_m = \frac{m~\lambda}{d}$ We can find $d$: $sin~\theta_2 = \frac{(2)~\lambda}{d}$ $d = \frac{(2)~\lambda}{sin~\theta_2}$ $d = \frac{(2)(620\times 10^{-9}~m)}{sin~39.5^{\circ}}$ $d = 1.95\times 10^{-6}~m$ We can find the number of lines per millimeter: $N = \frac{1.0\times 10^{-3}~m}{1.95\times 10^{-6}~m}$ $N = 513$ The grating has $~~513~~$ lines per millimeter.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.