General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 1 - Chemistry and Measurement - Questions and Problems - Page 37: 1.129

Answer

$m_{platinum}$ = 1822.9 g = 1.82 x $10^{3}$ g

Work Step by Step

From formula for density d = $\frac{m}{V}$ , we can write the formula to find the mass: m = d x V 1- First find the volume of the the cube of platinum . We know that $V_{cube}$ = $edge^{3}$ so $V_{cube of platinum}$ = $(4.40)^{3}cm^{3}$ = 85.18 $cm^{3}$ 2- Find the mass of the cube of platinum: m = d x V $m_{platinum}$ = 21.4 $\frac{g}{cm^{3}}$ x85.18 $cm^{3}$ $m_{platinum}$ = 1822.9 g. Or we can write the mass of platinum: $m_{platinum}$ = 1822.9 g = 1.82 x $10^{3}$ g
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