Answer
Calcite (2.76 $\frac{g}{cm^{3}}$) should float on tetrabromoethane ( 2.96 $\frac{g}{cm^{3}}$ ) and on methylene iodine ( 3.33 $\frac{g}{cm^{3}}$ ).
Work Step by Step
As a solid will float on any liquid that is more dense than it, we have to find the density of calcite and than compare it with the densities of the given liquid.
If $density_{calcite}$$\lt$$density_{liquid}$, than calcite will float on the liquid.
1- Find the density of the calcite:
d = $\frac{m}{V}$
$d_{calcite}$ = $\frac {35.6 g}{12.9 cm^{3}}$ = 2.76 $\frac{g}{cm^{3}}$
2- Compare the density of calcite with the densities of the liquids, and we see that only two liquids are more dense than calcite.
- Density of tetrabromoethane ( 2.96 $\frac{g}{cm^{3}}$ ) is greater than the density of calcite, so calcite should float on tetrabromoethane.
- Density of methylene iodine ( 3.33 $\frac{g}{cm^{3}}$ ) is greater than the density of calcite, so calcite should float on methylene iodine.
