General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 1 - Chemistry and Measurement - Questions and Problems - Page 37: 1.120

Answer

$T_{K}$ = 234 K $t_{F}$ = $-38^{0}$F

Work Step by Step

Formula to convert Celsius to Kelvin: $T_{K}$ = ($t_{C}$x$\frac{1 K}{1^{0}C}$) +273.15 K We know $t_{C}$ = $-38.9^{0}$C, so : $T_{K}$ = ($-38.9^{0}$Cx$\frac{1 K}{1^{0}C}$) +273.15 K $T_{K}$ = 234.25 K $T_{K}$ = 234 K To convert to Fahrenheit, apply the formula to convert Celsius to Fahrenheit: $t_{F}$ =($t_{C}$ x$\frac{9^{0}F}{5^{0}C}$) +$32^{0}$F We know $t_{C}$ = $-38.9^{0}$C, so : $t_{F}$ =($-38.9^{0}$C x$\frac{9^{0}F}{5^{0}C}$) +$32^{0}$F $t_{F}$ = $-70.02^{0}$F+$32^{0}$F $t_{F}$ = $-38.02^{0}$F $t_{F}$ = $-38^{0}$F
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.