General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 1 - Chemistry and Measurement - Questions and Problems - Page 37: 1.122

Answer

$t_{C}$ = $113^{0}$C $T_{K}$ = 386 K

Work Step by Step

We can convert temperature from Fahrenheit into Celsius, by applying the formula: $t_{C}$ = $\frac{5^{0}C}{9^{0}F}$ x ($t_{F}$-$32^{0}$F) We know $t_{F}$ = $236^{0}$F , so we can write: $t_{C}$ = $\frac{5^{0}C}{9^{0}F}$ x ($236^{0}$F-$32^{0}$F) $t_{C}$ = $\frac{5^{0}C}{9^{0}F}$ x$204^{0}$F $t_{C}$ = $113.33^{0}$C $t_{C}$ = $113^{0}$C Now that we know temperature in Celsius, we can apply formula to convert Celsius to Kelvin: $T_{K}$ = ($t_{C}$x$\frac{1 K}{1^{0}C}$) +273.15 K We know $t_{C}$ = $113^{0}$C, so : $T_{K}$ = ($113^{0}$Cx$\frac{1 K}{1^{0}C}$) +273.15 K $T_{K}$ = 386.15 K $T_{K}$ = 386 K
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