Answer
a - 3.47 x $10^{-2}$
b- 1.87
c - 5.58 x $10^{1}$
d - 1.76 x $10^{1}$
Work Step by Step
a -To find $\frac{9.345-9.005}{9.811}$
$\frac{9.345-9.005}{9.811}$ = $\frac{0.34}{9.811}$ = 0.0347
or 3.47 x $10^{-2}$
b - To find $\frac{9.345+9.005}{9.811}$
$\frac{9.345+9.005}{9.811}$ = $\frac{18.35}{9.811}$ = 1.87
c - To find:
(7.50 + 7.53) x 3.71 = 15.03x 3.71 = 55.76 . This number expressed to three significant figures is 55.8 or 5.58 x $10^{1}$
d - To find:
0.71 x 0.36+ 17.36 = 0.2556 +17.36 = 17.6156. This number can be written as 1.76 x $10^{1}$ ( to three significant figures)
