General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 1 - Chemistry and Measurement - Questions and Problems - Page 37: 1.109

Answer

a - 7.6 x $10^{-1}$ ( to three significant figures) b- 1.63 x $10^{1}$( to three significant figures) c- 4.76 x $10^{2}$ d- 1.12 x $10^{-1}$ ( to three significant figures)

Work Step by Step

a -To find $\frac{56.1-51.1}{6.58}$ $\frac{56.1-51.1}{6.58}$ = $\frac{5}{6.58}$ $\frac{56.1-51.1}{6.58}$ = 0.759 or $\frac{56.1-51.1}{6.58}$ = 0.76 ( to three significant figures) or 7.6 x $10^{-1}$ b - To find $\frac{56.1+51.1}{6.58}$ $\frac{56.1+51.1}{6.58}$ = $\frac{107.2}{6.58}$ $\frac{56.1+51.1}{6.58}$ = 16.29 or $\frac{56.1+51.1}{6.58}$ = 16.3 ( to three significant figures) or 1.63 x $10^{1}$ c - To find: (9.1 + 8.6) x 26.91 = 17.7 x 26.91 = 476.31 . This number expressed to three significant figures is 476 or 4.76 x $10^{2}$ d - To find: 0.0065 x 3.21 + 0.0911 = 0.0209 + 0.0911 = 0.1120. This number can be written as 1.12 x $10^{-1}$ ( to three significant figures)
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