General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 1 - Chemistry and Measurement - Questions and Problems - Page 37: 1.107

Answer

V = 9.9 x $10^{1}$ $cm^{3}$ ( to three significant figures)

Work Step by Step

First we have to find the volume of each sphere and than find the difference in volumes. For sphere with radius 5.61 cm: $V_{1}$ = $\frac{4}{3}\timesπ\times{r}^{3}$ $V_{1}$= $\frac{4}{3}\times3.14\times({5.61 cm})^{3}$ $V_{1}$= 739.19 $cm^{3}$ For sphere with radius 5.85 cm: $V_{2}$= $\frac{4}{3}\timesπ\times{r}^{3}$ $V_{2}$= $\frac{4}{3}\times3.14\times({5.85 cm})^{3}$ $V_{2}$= 838.18 $cm^{3}$ Difference: V = $V_{2}$ - $V_{1}$ V = 838.18 $cm^{3}$ - 739.19 $cm^{3}$ V = 98.98 $cm^{3}$ V = 9.898 x $10^{1}$ $cm^{3}$ V = 9.9 x $10^{1}$ $cm^{3}$ ( to three significant figures)
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