Answer
$fâ\left( x\right) =\dfrac {1}{2\sqrt {x-2}}$
$f'\left( 3\right) =\dfrac {1}{2}$
$f'\left( 4\right) =\dfrac {1}{2\sqrt {2}}$
Work Step by Step
$f\left( x\right) =\sqrt {x-2}=\left( x-2\right) ^{\dfrac {1}{2}}\rightarrow f'\left( x\right) =\dfrac {1}{2}\times \left( x-2\right) ^{\dfrac {1}{2}-1}\times \left( x-2\right)â=\dfrac {1}{2}\times \left( x-2\right) ^{-\dfrac {1}{2}}\times \left( 1\times x^{1-1}-0\right) =\dfrac {1}{2\sqrt {x-2}}$
$f'\left( 3\right) =\dfrac {1}{2\sqrt {x-2}}=\dfrac {1}{2\times \sqrt {3-2}}=\dfrac {1}{2\times \sqrt {1}}=\dfrac {1}{2}$
$f'\left( 4\right) =\dfrac {1}{2\sqrt {x-2}}=\dfrac {1}{2\times \sqrt {4-2}}=\dfrac {1}{2\times \sqrt {2}}=\dfrac {1}{2\sqrt {2}}$