Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.4 Factoring Polynomials - R.4 Exercises - Page 44: 96

Answer

$(2y-3)^2$

Work Step by Step

Treat $2y-1$ as a single unit and use the formula $a^2-2ab+b^2=(a-b)^2$, we have $(2y-1)^2-4(2y-1)+4=(2y-1-2)^2=(2y-3)^2$
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