Answer
$(4z^2+5)(z^2-3)$
Work Step by Step
Step 1. Let $z^2=y$, we can rewrite the expression as $4z^4-7z^2-15=4y^2-7y-15$
Step 2. $4y^2-7y-15=(4y+5)(y-3)$
Step 3. Use $y=z^2$, we have $4z^4-7z^2-15=(4z^2+5)(z^2-3)$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter R - Review of Basic Concepts - R.4 Factoring Polynomials - R.4 Exercises - Page 44: 114
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