Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.4 Factoring Polynomials - R.4 Exercises: 59

Answer

$\color{blue}{(3a+4)(3a-4)}$

Work Step by Step

Note that $9a^2=(3a)^2$ and $16=4^2$. Thus, the given binomial is equivalent to: $=(3a)^2-4^2$ Factor using the formula $a^2-b^2=(a+b)(a-b)$ where $a=3a$ and $b=4$ to obtain: $=\color{blue}{(3a+4)(3a-4)}$
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