Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.4 Factoring Polynomials - R.4 Exercises: 87

Answer

$\left( a+4\right) \left( a^{2}-a+7\right) $

Work Step by Step

$\left( a+1\right) ^{3}+27=\left( a+1\right) ^{3}+3^{3}=\left( \left( a+1\right) +3\right) \left( \left( a+1\right) ^{2}-3\left( a+1\right) +3^{2}\right) =\left( a+4\right) \left( a^{2}-a+7\right) $
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