Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.4 Factoring Polynomials - R.4 Exercises: 65

Answer

$\color{blue}{(a+b+4)(a+b-4))}$

Work Step by Step

Note that $16=4^2$. Thus, the binomial above is equivalent to: $=(a+b)^2-4^2$ Factor the binomial using the formula $x^2-y^2=(x+y)(x-y)$ where $x=a+b$ and $y=4$ to obtain: $=[(a+b)+4][(a+b)-4] \\=\color{blue}{(a+b+4)(a+b-4))}$
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