Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.4 Factoring Polynomials - R.4 Exercises: 89

Answer

$3\left( x+3\right) \left( 9x^{2}+25x+21\right) $

Work Step by Step

$\left( 3x+4\right) ^{3}-1=\left( 3x+4\right) ^{3}-1^{3}=\left( 3x+4-1\right) \left( \left( 3x+4\right) ^{2}+1\times \left( 3x+4\right) +1^{2}\right) =3\left( x+3\right) \left( 9x^{2}+25x+21\right) $
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