Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.4 Factoring Polynomials - R.4 Exercises: 63

Answer

$\color{blue}{(5s^2+3t)(5s^2-3t)}$

Work Step by Step

Note that $25s^4=(5s^2)^2$ and $9t^2=(3t)^2$. Thus, the given binomial is equivalent to: $=(5s^2)^2-(3t)^2$ Factor using the formula $a^2-b^2=(a+b)(a-b)$ where $a=5s^2$ and $b=3t$ to obtain: $=\color{blue}{(5s^2+3t)(5s^2-3t)}$
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