Answer
$90$
Work Step by Step
$\sum ^{5}_{i=1}\left( 5i+3\right) =\sum ^{5}_{i=1}5i+\sum ^{5}_{i=1}3=5\times \dfrac {n\left( n+1\right) }{2}+3\times n=5\times \dfrac {5\times \left( 5+1\right) }{2}+3\times 5=90$
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