Answer
$-2+(-\frac{1}{2})+0+\frac{1}{4}+\frac{2}{5}$
$=-\frac{37}{20}$
Work Step by Step
$\sum_{i=1}^5\frac{x_i}{x_i+3}$
$=\frac{x_1}{x_1+3}+\frac{x_2}{x_2+3}+\frac{x_3}{x_3+3}+\frac{x_4}{x_4+3}+\frac{x_5}{x_5+3}$
$=\frac{-2}{-2+3}+\frac{-1}{-1+3}+\frac{0}{0+3}+\frac{1}{1+3}+\frac{2}{2+3}$
$=-2+(-\frac{1}{2})+0+\frac{1}{4}+\frac{2}{5}$
$=\boxed{-\frac{37}{20}}$
